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question:solve this code advent problem in nodejs You reach the place where all of the mirrors were pointing: a massive parabolic reflector dish attached to the side of another large mountain. The dish is made up of many small mirrors, but while the mirrors themselves are roughly in the shape of a parabolic reflector dish, each individual mirror seems to be pointing in slightly the wrong direction. If the dish is meant to focus light, all it's doing right now is sending it in a vague direction. This system must be what provides the energy for the lava! If you focus the reflector dish, maybe you can go where it's pointing and use the light to fix the lava production. Upon closer inspection, the individual mirrors each appear to be connected via an elaborate system of ropes and pulleys to a large metal platform below the dish. The platform is covered in large rocks of various shapes. Depending on their position, the weight of the rocks deforms the platform, and the shape of the platform controls which ropes move and ultimately the focus of the dish. In short: if you move the rocks, you can focus the dish. The platform even has a control panel on the side that lets you tilt it in one of four directions! The rounded rocks (O) will roll when the platform is tilted, while the cube-shaped rocks (#) will stay in place. You note the positions of all of the empty spaces (.) and rocks (your puzzle input). For example: O....#.... O.OO#....# ........ OO.#O....O .O.....O#. O.#..O.#.# ..O..#O..O .......O.. #....#.. #OO..#.... Start by tilting the lever so all of the rocks will slide north as far as they will go: OOOO.#.O.. OO..#....# OO..O..O O..#.OO... ........#. ..#....#.# ..O..#.O.O ..O....... #....#.. #....#.... You notice that the support beams along the north side of the platform are damaged; to ensure the platform doesn't collapse, you should calculate the total load on the north support beams. The amount of load caused by a single rounded rock (O) is equal to the number of rows from the rock to the south edge of the platform, including the row the rock is on. (Cube-shaped rocks (#) don't contribute to load.) So, the amount of load caused by each rock in each row is as follows: OOOO.#.O.. 10 OO..#....# 9 OO..O..O 8 O..#.OO... 7 ........#. 6 ..#....#.# 5 ..O..#.O.O 4 ..O....... 3 #....#.. 2 #....#.... 1 The total load is the sum of the load caused by all of the rounded rocks. In this example, the total load is 136. Tilt the platform so that the rounded rocks all roll north. Afterward, what is the total load on the north support beams? To begin, get your puzzle input.
answer:As an AI developed by OpenAI, I don't have the ability to interact directly with external systems or fetch your unique puzzle input from the Advent of Code website. The Advent of Code problems often require participants to retrieve their input data from the website itself. However, I can certainly help you with a Node.js program that would solve the problem described, assuming you have the input data available in a text file. Below you will find a Node.js script that reads the input from a file named 'input.txt' and computes the total load on the north support beams after tilting all rounded rocks north. ```javascript const fs = require('fs'); // Read the input file and split by lines fs.readFile('input.txt', 'utf8', (err, data) => { if (err) { console.error('Error reading file:', err); return; } const lines = data.trim().split('n'); const height = lines.length; const width = lines[0].length; // Function to compute the load on the north support beams const calculateLoad = (array) => { let totalLoad = 0; // Process each row from the bottom to the top for (let y = height - 1; y >= 0; y--) { for (let x = 0; x < width; x++) { if (array[y][x] === 'O') { // Each rounded rock contributes to the load based on its distance from the bottom totalLoad += (height - y); } } } return totalLoad; }; // Initialize the grid based on the input const grid = lines.map(line => line.split('')); // Tilt all rounded rocks to the north for (let x = 0; x < width; x++) { for (let y = 0; y < height; y++) { if (grid[y][x] === 'O') { let newY = y; // Keep moving the rock north until it hits either the top or a cube-shaped rock while (newY > 0 && grid[newY - 1][x] === '.') { grid[newY - 1][x] = 'O'; grid[newY][x] = '.'; newY--; } } } } // Calculate the load on the north support beams const totalLoad = calculateLoad(grid); console.log('Total Load:', totalLoad); }); ``` Save this script as `main.js`, and make sure your input is in `input.txt`. Run the Node.js script using the command: ```bash node main.js ``` The program will output the total load on the north support beams after tilting all the rounded rocks north. Please keep in mind that you should replace 'input.txt' with the actual path to your input file, and ensure your input data is in the expected format as described in the problem.
question:--- Day 6: Wait For It --- The ferry quickly brings you across Island Island. After asking around, you discover that there is indeed normally a large pile of sand somewhere near here, but you don't see anything besides lots of water and the small island where the ferry has docked. As you try to figure out what to do next, you notice a poster on a wall near the ferry dock. "Boat races! Open to the public! Grand prize is an all-expenses-paid trip to Desert Island!" That must be where the sand comes from! Best of all, the boat races are starting in just a few minutes. You manage to sign up as a competitor in the boat races just in time. The organizer explains that it's not really a traditional race - instead, you will get a fixed amount of time during which your boat has to travel as far as it can, and you win if your boat goes the farthest. As part of signing up, you get a sheet of paper (your puzzle input) that lists the time allowed for each race and also the best distance ever recorded in that race. To guarantee you win the grand prize, you need to make sure you go farther in each race than the current record holder. The organizer brings you over to the area where the boat races are held. The boats are much smaller than you expected - they're actually toy boats, each with a big button on top. Holding down the button charges the boat, and releasing the button allows the boat to move. Boats move faster if their button was held longer, but time spent holding the button counts against the total race time. You can only hold the button at the start of the race, and boats don't move until the button is released. For example: Time: 7 15 30 Distance: 9 40 200 This document describes three races: The first race lasts 7 milliseconds. The record distance in this race is 9 millimeters. The second race lasts 15 milliseconds. The record distance in this race is 40 millimeters. The third race lasts 30 milliseconds. The record distance in this race is 200 millimeters. Your toy boat has a starting speed of zero millimeters per millisecond. For each whole millisecond you spend at the beginning of the race holding down the button, the boat's speed increases by one millimeter per millisecond. So, because the first race lasts 7 milliseconds, you only have a few options: Don't hold the button at all (that is, hold it for 0 milliseconds) at the start of the race. The boat won't move; it will have traveled 0 millimeters by the end of the race. Hold the button for 1 millisecond at the start of the race. Then, the boat will travel at a speed of 1 millimeter per millisecond for 6 milliseconds, reaching a total distance traveled of 6 millimeters. Hold the button for 2 milliseconds, giving the boat a speed of 2 millimeters per millisecond. It will then get 5 milliseconds to move, reaching a total distance of 10 millimeters. Hold the button for 3 milliseconds. After its remaining 4 milliseconds of travel time, the boat will have gone 12 millimeters. Hold the button for 4 milliseconds. After its remaining 3 milliseconds of travel time, the boat will have gone 12 millimeters. Hold the button for 5 milliseconds, causing the boat to travel a total of 10 millimeters. Hold the button for 6 milliseconds, causing the boat to travel a total of 6 millimeters. Hold the button for 7 milliseconds. That's the entire duration of the race. You never let go of the button. The boat can't move until you let go of the button. Please make sure you let go of the button so the boat gets to move. 0 millimeters. Since the current record for this race is 9 millimeters, there are actually 4 different ways you could win: you could hold the button for 2, 3, 4, or 5 milliseconds at the start of the race. In the second race, you could hold the button for at least 4 milliseconds and at most 11 milliseconds and beat the record, a total of 8 different ways to win. In the third race, you could hold the button for at least 11 milliseconds and no more than 19 milliseconds and still beat the record, a total of 9 ways you could win. To see how much margin of error you have, determine the number of ways you can beat the record in each race; in this example, if you multiply these values together, you get 288 (4 * 8 * 9). Determine the number of ways you could beat the record in each race. What do you get if you multiply these numbers together? To begin, get your puzzle input. The code must also use the latest JS features
answer:Please note that to compute the number of ways you could beat the record in each race and multiply these numbers together using the latest JavaScript features, you will need the puzzle input. Since I don't have access to the Advent of Code platform to fetch the puzzle input, you'll need to supply this information. The problem can be solved by understanding that for each race, you need to maximize the distance traveled within the given time. The distance traveled is the result of integrating the velocity function since the boat's speed increases linearly with the time the button is held down. Assuming you have your input in a `puzzleInput` variable structured as an array of objects where each object has a `time` and `record` property like so: ```javascript const puzzleInput = [ { time: 7, distance: 9 }, { time: 15, distance: 40 }, { time: 30, distance: 200 }, // ... additional races ]; ``` You could use the following Node.js code to compute your solution: ```javascript const puzzleInput = [ { time: 7, distance: 9 }, { time: 15, distance: 40 }, { time: 30, distance: 200 }, // Include your actual puzzle input here ]; // Compute the ways to beat the record for each race const waysToBeatRecords = puzzleInput.map(race => { let ways = 0; // Calculate possible outcomes for each holding time for (let holdTime = 1; holdTime < race.time; holdTime++) { let speed = holdTime; // Speed increases by 1mm/ms for each ms held let travelTime = race.time - holdTime; // Remaining time after button is released let distance = speed * travelTime; // Total distance covered at constant speed if (distance > race.distance) { // If we beat the record, increment the number of ways ways++; } } return ways; }); // Multiply the values together const productOfWays = waysToBeatRecords.reduce((acc, val) => acc * val, 1); console.log('Number of ways you could beat the record in each race:', waysToBeatRecords); console.log('Product of all ways:', productOfWays); ``` Before running the above code, replace the placeholder `puzzleInput` array with your actual input. This script will calculate the number of ways you can hold the button down to beat the record for each race, and then it will multiply those numbers to give you the final product. To run this code, paste it into a file named `solution.js` (for example) and run it with Node.js by executing `node solution.js` in the terminal. Remember that this code assumes the structure of the input is as provided. You may need to adjust the input reading mechanism depending on the actual format of your data.
question:const puzzleInput = [ { time: 47, distance: 400 }, { time: 98, distance: 1213 }, { time: 66, distance: 1011 }, { time: 98, distance: 1540 } ]; const waysToBeatRecords = puzzleInput.map(race => { let ways = 0; for (let holdTime = 1; holdTime < race.time; holdTime++) { let speed = holdTime; let travelTime = race.time - holdTime; let distance = speed * travelTime; if (distance > race.distance) { ways++; } } return ways; }); const productOfWays = waysToBeatRecords.reduce((acc, val) => acc * val, 1); console.log('Number of ways you could beat the record in each race:', waysToBeatRecords); console.log('Product of all ways:', productOfWays); Is there a better logic / way to write this solution?
answer:The given script correctly calculates the number of ways to beat the record in each race and then multiplies these numbers together. However, we can optimize the loop by finding the maximum hold time that still allows the boat to beat the record, using a mathematical approach rather than iteration for each hold time. We know the relationship between hold time, travel time, and distance is given by: ``` distance = speed * travelTime ``` since speed increases by 1 mm/ms each millisecond the button is held, and speed is equivalent to the hold time (`speed = holdTime`), we can say: ``` distance = holdTime * (race.time - holdTime) ``` We need to find the largest `holdTime` such that `distance > race.distance`. `distance` forms a quadratic equation with respect to `holdTime`, and since it's a parabola opening downwards (because of the `-holdTime^2` term), the vertex will give us the maximum possible distance. The vertex of the parabola `ax^2 + bx + c` is at `x = -b / (2a)`. For our equation, `a = -1`, `b = race.time`, therefore the vertex is at: ``` holdTime = race.time / 2 ``` The methods to beat the record will be symmetric around this vertex. We will find the integer value of `holdTime` just under this vertex that results in a qualifying distance, which will be our maximum hold time: ```javascript const puzzleInput = [ { time: 47, distance: 400 }, { time: 98, distance: 1213 }, { time: 66, distance: 1011 }, { time: 98, distance: 1540 }, ]; const waysToBeatRecords = puzzleInput.map(race => { let maxHoldTime = Math.floor(race.time / 2); let maxDistance = maxHoldTime * (race.time - maxHoldTime); if (maxDistance <= race.distance) { return 0; // No possible way to beat the record } while (maxHoldTime > 0 && (maxHoldTime * (race.time - maxHoldTime) <= race.distance)) { maxHoldTime--; } // Since the outcomes are symmetrical around the vertex, we can double the calculation from the starting point to the vertex. return (maxHoldTime * 2) - (race.time % 2 === 0 ? 1 : 0); }); const productOfWays = waysToBeatRecords.reduce((acc, val) => acc * val, 1); console.log('Number of ways you could beat the record in each race:', waysToBeatRecords); console.log('Product of all ways:', productOfWays); ``` The conditional `(race.time % 2 === 0 ? 1 : 0)` is there to avoid counting the vertex twice when the total race time is even. If the race time is odd, there is a single max value between two integers on either side of the vertex. If even, the maximal distance is achieved on both sides of the vertex equally, we subtract one to avoid counting twice. This approach reduces the number of iterations needed for each race, as it requires finding just one `holdTime` per race instead of iterating over all possible hold times.
question:--- Day 7: Camel Cards --- Your all-expenses-paid trip turns out to be a one-way, five-minute ride in an airship. (At least it's a cool airship!) It drops you off at the edge of a vast desert and descends back to Island Island. "Did you bring the parts?" You turn around to see an Elf completely covered in white clothing, wearing goggles, and riding a large camel. "Did you bring the parts?" she asks again, louder this time. You aren't sure what parts she's looking for; you're here to figure out why the sand stopped. "The parts! For the sand, yes! Come with me; I will show you." She beckons you onto the camel. After riding a bit across the sands of Desert Island, you can see what look like very large rocks covering half of the horizon. The Elf explains that the rocks are all along the part of Desert Island that is directly above Island Island, making it hard to even get there. Normally, they use big machines to move the rocks and filter the sand, but the machines have broken down because Desert Island recently stopped receiving the parts they need to fix the machines. You've already assumed it'll be your job to figure out why the parts stopped when she asks if you can help. You agree automatically. Because the journey will take a few days, she offers to teach you the game of Camel Cards. Camel Cards is sort of similar to poker except it's designed to be easier to play while riding a camel. In Camel Cards, you get a list of hands, and your goal is to order them based on the strength of each hand. A hand consists of five cards labeled one of A, K, Q, J, T, 9, 8, 7, 6, 5, 4, 3, or 2. The relative strength of each card follows this order, where A is the highest and 2 is the lowest. Every hand is exactly one type. From strongest to weakest, they are: Five of a kind, where all five cards have the same label: AAAAA Four of a kind, where four cards have the same label and one card has a different label: AA8AA Full house, where three cards have the same label, and the remaining two cards share a different label: 23332 Three of a kind, where three cards have the same label, and the remaining two cards are each different from any other card in the hand: TTT98 Two pair, where two cards share one label, two other cards share a second label, and the remaining card has a third label: 23432 One pair, where two cards share one label, and the other three cards have a different label from the pair and each other: A23A4 High card, where all cards' labels are distinct: 23456 Hands are primarily ordered based on type; for example, every full house is stronger than any three of a kind. If two hands have the same type, a second ordering rule takes effect. Start by comparing the first card in each hand. If these cards are different, the hand with the stronger first card is considered stronger. If the first card in each hand have the same label, however, then move on to considering the second card in each hand. If they differ, the hand with the higher second card wins; otherwise, continue with the third card in each hand, then the fourth, then the fifth. So, 33332 and 2AAAA are both four of a kind hands, but 33332 is stronger because its first card is stronger. Similarly, 77888 and 77788 are both a full house, but 77888 is stronger because its third card is stronger (and both hands have the same first and second card). To play Camel Cards, you are given a list of hands and their corresponding bid (your puzzle input). For example: 32T3K 765 T55J5 684 KK677 28 KTJJT 220 QQQJA 483 This example shows five hands; each hand is followed by its bid amount. Each hand wins an amount equal to its bid multiplied by its rank, where the weakest hand gets rank 1, the second-weakest hand gets rank 2, and so on up to the strongest hand. Because there are five hands in this example, the strongest hand will have rank 5 and its bid will be multiplied by 5. So, the first step is to put the hands in order of strength: 32T3K is the only one pair and the other hands are all a stronger type, so it gets rank 1. KK677 and KTJJT are both two pair. Their first cards both have the same label, but the second card of KK677 is stronger (K vs T), so KTJJT gets rank 2 and KK677 gets rank 3. T55J5 and QQQJA are both three of a kind. QQQJA has a stronger first card, so it gets rank 5 and T55J5 gets rank 4. Now, you can determine the total winnings of this set of hands by adding up the result of multiplying each hand's bid with its rank (765 * 1 + 220 * 2 + 28 * 3 + 684 * 4 + 483 * 5). So the total winnings in this example are 6440. Find the rank of every hand in your set. What are the total winnings? Here's your puzzle input T6JTT 716 8J29Q 523 486TK 358 3AAAA 945 J5552 239 38AJ8 703 K8Q88 653 7634K 905 A222A 390 AAJAA 317 288Q2 825 KQ77Q 107 JJ7K7 249 QQ4JJ 519 433J9 411 T6TTT 304 K59KK 178 QQQTT 524 AQKQ6 21 Q8886 853 79J6J 84 33Q3Q 740 TAJA2 998 464A4 584 55667 686 QTT6Q 810 A9799 708 5643T 157 353AK 319 228JK 466 44TTT 760 85637 553 9K9A4 897 A9J8A 334 QKQQ5 600 8QA5A 200 33823 273 J228A 345 65668 986 KA8K7 101 4A735 791 55A55 901 7727Q 301 889J9 494 44848 134 98298 408 83KK3 562 T48T4 587 46626 190 J425K 568 787JJ 739 T8JJQ 573 62J8K 976 9JJ99 823 7777J 860 J3KA2 1 65646 843 78877 316 JJ888 614 527KT 765 AA9AA 124 4774A 370 AT97Q 727 4J274 870 99J79 834 72479 387 T6343 623 7534K 426 226A2 194 3TQQ8 625 T3T33 492 8J472 895 JKKK8 641 66596 535 494QA 887 99333 388 JQJ55 793 3A373 179 85588 948 AATAA 3 52827 570 KKJ33 593 53A4K 246 JK3TQ 293 32442 530 434A9 842 KK5K6 154 49J48 714 79TA5 199 7K79K 542 T9TTT 916 92994 811 66676 306 K5JK5 490 59AQ6 285 A5A33 32 22282 833 982Q9 181 88388 63 QAQQ5 522 67454 717 8JT33 855 84888 997 2J2TQ 392 JTT8T 34 9399Q 457 687J8 541 2Q22J 391 66KK6 29 KQ2K2 350 777QQ 652 2TT33 911 T7272 250 3846T 375 KQ435 502 44333 96 Q8Q5Q 177 6668J 106 88262 772 JKAAK 170 5Q555 235 7666A 232 TJ777 123 K3K87 415 996Q5 113 TT555 683 2992J 707 67787 226 AQKJ9 909 A97KJ 926 Q2JQ6 109 6TA94 508 9K99K 993 KJK4A 732 56J28 598 88544 751 63577 39 3T4KK 382 KA948 747 3JTTQ 588 QAQT5 629 TTTT2 13 JA5KA 942 22QTT 114 A8A6A 186 3AA7A 832 K224T 912 5TKTJ 808 KJ3T9 947 3TJ43 55 25229 4 7QK25 696 T9JQ4 126 88577 288 J28K9 187 75579 621 KJ8QK 846 QK4T6 356 K574Q 478 9JJJ9 500 6J343 176 96666 734 T8JTJ 159 66J76 658 87A4T 308 66J66 725 A3Q44 520 Q668J 946 J22TJ 874 Q6466 719 325Q6 422 33T33 486 4AA2J 171 44297 512 92399 569 552TT 513 66J69 831 TKT99 768 44448 464 K4A44 787 JQJQ3 979 79QQQ 204 3KKK3 699 4T458 501 J894K 10 88K8K 260 77775 58 7J788 335 99969 401 82594 41 J98Q8 921 222JK 443 6549J 525 43423 436 9J949 908 A8Q95 555 4A235 394 57535 236 22J22 618 28QA6 326 74455 792 AATJA 477 4AJA4 960 4649A 264 2KK55 405 44J34 809 6J545 964 23323 36 AA266 476 9Q99Q 620 2J8T3 940 99997 851 62ATT 270 8JAA8 817 8A334 127 K4368 788 66Q23 148 672KJ 480 2K59J 68 36Q6K 69 35335 515 AAA33 321 K9474 670 49848 951 55J55 840 4T444 320 4Q89A 78 6K6J6 66 4J5TA 131 T958K 31 2Q74Q 928 AQQAQ 71 27598 169 J5995 287 K4T48 820 K55K3 532 22A32 25 272T4 576 668J7 440 Q9QQQ 742 AQ9TK 929 J76TK 968 9J66A 208 68QKQ 213 33373 82 JA2A2 859 25K2J 424 AK33K 247 2835Q 309 26262 702 QK3QQ 234 KK4K8 818 8T7TQ 611 46TJK 953 9J699 949 TT44J 757 92A77 459 47477 784 J9JAQ 245 65JKT 377 65J56 991 6QQ6Q 315 TJA9J 423 J5455 141 94949 565 QA26K 447 99Q99 117 2J779 824 KQ9Q4 505 KKKKA 110 TT83T 977 K55J7 826 44QQJ 795 Q4Q44 380 35333 189 6Q878 774 66336 746 T2222 781 8K888 445 9964Q 715 88J8K 104 J9999 995 8Q77T 351 426K5 5 K9K9K 581 9T22T 944 A45A6 927 27J27 147 47474 258 Q78QQ 983 77797 389 Q4Q64 384 AQKJ3 279 22Q35 52 3K3J5 759 37JQQ 129 QA688 559 J8JJJ 271 9365T 627 4K9K2 962 3TT3T 894 8Q7JT 328 2552Q 694 4K98K 789 2T555 45 25469 721 83TTA 982 272K2 140 6T235 816 KAAKT 580 TT89T 586 46A67 920 63686 959 8K457 965 TTJAT 57 6K6JK 780 842J9 455 JKKKQ 654 77232 175 4A444 830 9KA99 302 QT6TT 324 Q88Q8 402 24937 575 AA96A 357 98599 799 97499 917 JAT87 296 J474Q 904 A88Q8 722 55223 192 Q5939 504 622J2 649 JKKKK 50 AJ3Q9 160 58AJ2 753 452T7 277 JATT4 589 33363 841 64747 661 2KK2K 764 JTJT3 709 AJJA3 850 K6T59 48 929Q7 626 5A6TK 156 K26T9 161 TAAA2 307 3TTTT 136 Q9Q5Q 120 T5468 289 44454 647 AJ333 105 KK63K 521 J8388 952 99T9T 139 53232 821 484J3 26 66J85 790 2228Q 27 TT737 212 55754 470 5Q666 943 6J48T 578 8AA66 941 33323 215 A22TA 680 QQQTQ 755 62222 882 A964J 371 8QQQJ 679 A99AK 497 2KJTJ 481 T8Q6J 479 799AA 379 4T672 880 448T8 607 66868 329 K66KT 975 44664 974 J4423 1000 66922 488 T335T 115 T55T3 28 3A9A3 431 57575 891 74AJJ 773 QAKKQ 534 A74A7 984 3KJ33 603 QA7JK 460 87728 331 7TJ7T 354 99995 432 A5T25 97 55T55 242 T8669 410 J8A2A 228 9T7J7 318 Q4JQQ 805 88886 360 6T75T 552 QAAQA 310 T355Q 149 QQ8QQ 622 9QQQ9 22 K9849 257 9962T 672 999K9 981 JJ7T9 640 55JQ5 230 99T99 735 QK23J 599 4Q774 866 AK9JA 17 T6Q2Q 720 Q8K46 474 5J96T 280 4A5TT 499 T4QTQ 776 33977 263 T5429 60 575J6 954 ATTTT 491 T656T 376 J7A7A 971 JJTAT 879 A6686 385 94999 8 QQ99A 229 958TQ 248 68597 583 8885J 591 24355 963 JT5A3 251 95993 676 QJ556 80 3K8K8 881 96892 803 99Q9A 838 25K8J 441 444J4 752 J3J33 634 2A26A 907 3J3T3 561 67A47 217 8273K 303 TAK9K 967 476T7 711 4J3T9 632 48Q9Q 173 33K36 737 3QQ44 433 JTTT5 845 5555K 869 64K82 238 28288 689 869J7 83 777K5 314 9KJK9 617 54544 844 44456 723 337QJ 397 4K6Q2 413 65695 980 KTJT3 262 6KQ35 543 Q4Q77 462 5952K 900 AJAJA 861 T57TJ 992 K55QA 681 JTJ73 366 999QT 77 TKKJK 343 44242 330 447AA 241 AKKKJ 786 73243 152 343KT 227 95A59 495 A25Q5 9 29923 222 ATA8T 615 6JK7K 163 5TTTT 876 692A8 514 QQ733 338 6Q5JA 985 76Q53 987 JJ4J2 517 T829T 744 69969 966 22K26 442 8J833 467 8T889 763 5J947 955 6JQQ8 218 J83J5 518 K5KKK 243 459K2 463 QJQAJ 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answer:To efficiently solve the "Camel Cards" puzzle, you need to evaluate each hand to determine its type and then compare hands of the same type by their high cards according to the game rules. Here's a JavaScript function to calculate the hand rankings and total winnings. This function includes the hand evaluation and comparison logic, as well as modern JavaScript features such as the spread operator and `Array.sort()` with a custom comparator. ```javascript const puzzleInput = [ // ... include your puzzle input array of objects here ]; // Maps to convert card labels to numerical values and vice versa. const cardValueMap = { '2': 1, '3': 2, '4': 3, '5': 4, '6': 5, '7': 6, '8': 7, '9': 8, 'T': 9, 'J': 10, 'Q': 11, 'K': 12, 'A': 13 }; const valueCardMap = Object.fromEntries(Object.entries(cardValueMap).map(([k, v]) => [v, k])); // Evaluates a hand and returns its rank and sorted cards for comparison. const evaluateHand = (hand) => { const cards = hand.split('').sort((a, b) => cardValueMap[b] - cardValueMap[a]); const counts = {}; cards.forEach(card => counts[card] = (counts[card] || 0) + 1); const types = Object.entries(counts).sort((a, b) => b[1] - a[1]); const sortedByFrequencyThenValue = types.flatMap(([card, count]) => Array(count).fill(card)); const rank = types[0][1] === 4 ? 1 : types[0][1] === 3 && types[1][1] === 2 ? 2 : types[0][1] === 3 ? 3 : types[0][1] === 2 && types[1][1] === 2 ? 4 : types[0][1] === 2 ? 5 : 6; return { rank, cards: sortedByFrequencyThenValue.map(card => cardValueMap[card]), }; }; // Custom comparator to sort hands by their ranks and high cards. const handComparator = (a, b) => { const rankDiff = a.rank - b.rank; if (rankDiff !== 0) return rankDiff; for (let i = 0; i < a.cards.length; i++) { if (a.cards[i] !== b.cards[i]) { return b.cards[i] - a.cards[i]; } } return 0; }; // Map each hand to its evaluated form, including the associated bid, and then sort the resulting array. const evaluatedHands = puzzleInput.map(input => ({ ...evaluateHand(input.hand), bid: input.bid })); evaluatedHands.sort(handComparator); // Calculate total winnings using the ranks after sorting. const totalWinnings = evaluatedHands.reduce((acc, hand, index) => acc + hand.bid * (index + 1), 0); console.log('Total winnings:', totalWinnings); ``` Here's how the solution works in steps: 1. It maps each card label to a numerical value and defines `evaluateHand` that returns the rank and sorted cards for a given hand based on the game's rules. 2. It defines a custom comparator `handComparator` to sort the hands by their ranks and high cards. 3. It uses the `evaluateHand` function to create an array of evaluated hands with their associated bids and then sorts this array using the `handComparator`. 4. It calculates the total winnings by multiplying the rank (which is now the index in the sorted array + 1) by the associated bid for each hand. Before running the above code, replace the `// ... include your puzzle input array of objects here` comment with your actual parsed puzzle input (`{hand: 'XXXXX', bid: N}`), ensuring each object in the array contains the `hand` string and the `bid` number. After incorporating your actual input data, you can run the code to obtain the total winnings.